2x^2/3+3x^1/3-2=0

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Solution for 2x^2/3+3x^1/3-2=0 equation:


x in (-oo:+oo)

(2*x^2)/3+(3*x^1)/3-2 = 0

(2*x^2)/3+(3*x)/3-2 = 0

2/3*x^2+x-2 = 0

DELTA = 1^2-(-2*2/3*4)

DELTA = 19/3

DELTA > 0

x = ((19/3)^(1/2)-1)/(2/3*2) or x = (-(19/3)^(1/2)-1)/(2/3*2)

x = 3/4*((19/3)^(1/2)-1) or x = -3/4*((19/3)^(1/2)+1)

x in { -3/4*((19/3)^(1/2)+1), 3/4*((19/3)^(1/2)-1) }

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